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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int n;
  5. 	scanf("%d",&n);
  6. 	int sgn=(n>0)-(n<0);
  7. 	printf("%d",sgn);
  8. 	return 0;
  9. }
  10.  
Success #stdin #stdout 0.01s 5288KB
comments (?)
stdin 
3
stdout 
1
https://ideone.com/Z8YLQo
BASIC 的 SGN 函數 ，不用if
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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