import java.util.*;
class Quad2P {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
 
        long n = sc.nextLong();
        long k1 = sc.nextLong();
        long k2 = sc.nextLong();
 
        long[] a = new long[(int)n + 2]; // n+1 size with 1-based indexing
 
        for (int i = 1; i <= n; i++) {
            a[i] = sc.nextLong();
        }
 
        long c = 0;
        for(int i = 2; i<=n-2; i++){
            long c1=0;
            // count curr elem compatibility with all prev elem
            // we dont do j-i+1 coz single elem not counted(no +1) 
            // and its valid only if k,l are there to.. so i,j need to be valid 
            //first.. (i,j) <k is one prob and if a pair is true then see (k,l) if 0 k,l then 0*c2
            int j = 1;
            while(j<=(i-1)){
                if(a[i]+a[j]>k1){
                    c1++;
                }
                j++;
            }
            long c2=0;
            int k = i+1, l = (int)n;
            while(k<l){
                if(a[k]+a[l]>k2){
                    c2 += l-k;
                    l--; 
                    // check for a lesser window now.. we know that k.. l true, move on and see if k.. l-1
                }
                else{
                    k++; // we need a greater elem to pair w l and make it >k2
                }
            }
            c+= c1*c2;
        }
 
        System.out.println(c);
    }
}
 

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